If one of the angles formed by two intersecting lines is a right angle,what can you say about the other three angles? Give reason for your answer.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(D) Let two lines $AB$ and $CD$ intersect at point $O$. Let $\angle AOC = 90^\circ$.
Since $AB$ is a straight line,$\angle AOC + \angle BOC = 180^\circ$ (Linear pair axiom).
$90^\circ + \angle BOC = 180^\circ \implies \angle BOC = 90^\circ$.
Similarly,$\angle AOC + \angle AOD = 180^\circ$ (Linear pair axiom).
$90^\circ + \angle AOD = 180^\circ \implies \angle AOD = 90^\circ$.
Finally,$\angle AOD + \angle BOD = 180^\circ$ (Linear pair axiom).
$90^\circ + \angle BOD = 180^\circ \implies \angle BOD = 90^\circ$.
Therefore,all other three angles are also right angles $(90^\circ)$.

Explore More

Similar Questions

In $\Delta ABC$,the sides $AB$ and $AC$ are produced to $D$ and $E$ respectively,so that exterior angles $\angle CBD$ and $\angle BCE$ are formed. If bisectors of $\angle CBD$ and $\angle BCE$ intersect at point $O$,prove that $\angle BOC = 90^{\circ} - \frac{1}{2} \angle A$.

Difficult
View Solution

$\angle PRT$ is an exterior angle of $\Delta PQR$. If $\angle P = 70^{\circ}$ and $\angle Q = 50^{\circ}$,then $\angle PRT = \ldots$ (in $^{\circ}$)

In $\Delta PQR$,$\angle P = 42^{\circ}$ and $\angle Q = 75^{\circ}$,then find $\angle R$. (in $^{\circ}$)

In the figure,$BA \parallel ED$ and $BC \parallel EF.$ Show that $\angle ABC = \angle DEF.$

In the given figure,if $AB \parallel CD$,$\angle AXY = 80^{\circ}$ and $\angle XZD = 140^{\circ}$,then find $x$ and $y$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo