If matrix A = begin{bmatrix} 1 & -1 1 & 1 en | vedclass

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(C) Given $A = \begin{bmatrix} 1 & -1 \ 1 & 1 \end{bmatrix}$.We check option $(c)$: $A \begin{bmatrix} 1 & 1 \ -1 & 1 \end{bmatrix} = \begin{bmatrix

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$A \begin{bmatrix} 1 & 1 \ -1 & 1 \end{bmatrix} = 2I$

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(C) Given $A = \begin{bmatrix} 1 & -1 \ 1 & 1 \end{bmatrix}$.We check option $(c)$: $A \begin{bmatrix} 1 & 1 \ -1 & 1 \end{bmatrix} = \begin{bmatrix} 1 & -1 \ 1 & 1 \end{bmatrix} \begin{bmatrix} 1 & 1 \ -1 & 1 \end{bmatrix}$.Performing matrix multiplication:$= \begin{bmatrix} (1)(1) + (-1)(-1) & (1)(1) + (-1)(1) \ (1)(1) + (1)(-1) & (1)(1) + (1)(1) \end{bmatrix}$$= \begin{bmatrix} 1 + 1 & 1 - 1 \ 1 - 1 & 1 + 1 \end{bmatrix}$$= \begin{bmatrix} 2 & 0 \ 0 & 2 \end{bmatrix} = 2 \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix} = 2I$.Thus,option $(c)$ is correct.

If matrix $A = \begin{bmatrix} 1 & -1 \\ 1 & 1 \end{bmatrix}$,then:

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