If in the word CERTIFICATE,the first and the | vedclass

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(B) The word is $CERTIFICATE$. The total number of letters is $11$.The letters are: $1:C, 2:E, 3:R, 4:T, 5:I, 6:F, 7:I, 8:C, 9:A, 10:T, 11:E$.Accordin

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$R$

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(B) The word is $CERTIFICATE$. The total number of letters is $11$.The letters are: $1:C, 2:E, 3:R, 4:T, 5:I, 6:F, 7:I, 8:C, 9:A, 10:T, 11:E$.According to the rule,we interchange the pairs: $(1,7), (2,8), (3,9), (4,10), (5,11)$.Original: $C, E, R, T, I, F, I, C, A, T, E$New positions:$1 leftrightarrow 7: I, E, R, T, I, F, C, C, A, T, E$$2 leftrightarrow 8: I, C, R, T, I, F, C, E, A, T, E$$3 leftrightarrow 9: I, C, A, T, I, F, C, E, R, T, E$$4 leftrightarrow 10: I, C, A, T, I, F, C, E, R, T, E ightarrow I, C, A, T, I, F, C, E, R, T, E$Wait,let's re-map carefully:Original: $C(1), E(2), R(3), T(4), I(5), F(6), I(7), C(8), A(9), T(10), E(11)$After swapping $(1,7), (2,8), (3,9), (4,10), (5,11)$:New word: $I, C, A, T, E, F, C, E, R, T, T$Wait,let's re-index: $I(1), C(2), A(3), T(4), E(5), F(6), C(7), E(8), R(9), T(10), T(11)$.We need the third to the right of the sixth from the right end.Sixth from the right end is the $6^{th}$ letter from the end: $11, 10, 9, 8, 7, 6$. The $6^{th}$ letter is $F$.Third to the right of $F$ is the $3^{rd}$ letter to the right of $F$ (towards the end): $F(6), C(7), E(8), R(9)$.The letter is $R$.

If in the word $CERTIFICATE$,the first and the seventh letters are interchanged,similarly the second and the eighth letters are interchanged and so on up to the fifth and eleventh letters are interchanged,then which letter will be third to the right of sixth from the right end?

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