If a given wave has a propagation constant of $\frac{5 \pi}{7} \, rad/m$,then the phase difference between two particles having a distance difference of $\frac{49}{22} \, m$ is ..... $rad.$ (Take $\pi = \frac{22}{7}$)

  • A
    $5$
  • B
    $10$
  • C
    $2.5$
  • D
    $5/7$

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