If frequency, of ' A ' allele is 0.4 | vedclass

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Question

HW Principle $=p+q=1$

$p^{2}+2 p q+q^{2}=1$

Here, $p=A$ and $q$ is $=B$

Allele frequency of $B=1-0.4=0.6$

Allele frequency of heterozygous

Vedclass · Accepted Answer

$0.6$ and $0.48$

Vedclass · Answer

HW Principle $=p+q=1$

$p^{2}+2 p q+q^{2}=1$

Here, $p=A$ and $q$ is $=B$

Allele frequency of $B=1-0.4=0.6$

Allele frequency of heterozygous is $=2 	imes 0.6 	imes 0.4$

$	herefore 0.48$

If frequency, of ' $A$ ' allele is $0.4$ than, find out the frequency of ' $B$ ' allele and heterozygous genotype in a random mating population at equilibria

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