In a population of 1000 individuals 360 belon | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(c) : According to Hardy Weinberg principle,

$p^2 + 2pq + q^2 = 1; (p + q)^2 = 1$

$(AA)\ p^2 = 360$ out of $1000$ individual

or $p^2 = 0.36$

Vedclass · Accepted Answer

$0.6$

Vedclass · Answer

(c) : According to Hardy Weinberg principle,

$p^2 + 2pq + q^2 = 1; (p + q)^2 = 1$

$(AA)\ p^2 = 360$ out of $1000$ individual

or $p^2 = 0.36$ Therefore, $p = 0.6$

In a population of $1000$ individuals $360$ belong to genotype $AA, 480$ to Aa and the remaining $160$ to $aa$. Based on this data, the frequency of allele $A$ in the population is

Similar Questions

Random genetic drift in a population probably results from

Which is the most common mechanism of genetic variation in the population of a sexually reproducing organism ?

The frequency of an allele in an isolated population may change due to

Random unidirectional change in allele frequencies that occurs by chance in all populations and especially in small populations is known as

Natural selection in which more individuals acquire peripheral character value at both the ends of the distribution curve is