In a population of 1000 individuals 360 belon | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(c) : According to Hardy Weinberg principle,

$p^2 + 2pq + q^2 = 1; (p + q)^2 = 1$

$(AA)\ p^2 = 360$ out of $1000$ individual

or $p^2 = 0.36$

Vedclass · Accepted Answer

$0.6$

Vedclass · Answer

(c) : According to Hardy Weinberg principle,

$p^2 + 2pq + q^2 = 1; (p + q)^2 = 1$

$(AA)\ p^2 = 360$ out of $1000$ individual

or $p^2 = 0.36$ Therefore, $p = 0.6$

In a population of $1000$ individuals $360$ belong to genotype $AA, 480$ to Aa and the remaining $160$ to $aa$. Based on this data, the frequency of allele $A$ in the population is

Similar Questions

A population is in Hardy- weinberg equilibrium for a gene with only two alleles. If the gene frequency of an allele $A$ is $0.7$, the genotype frequency of $Aa$ is

Name the law that states that the sum of allelic frequencies in a population remains constant. What are the five factors that influence these values ?

Which one of the following factors will not affect the Hardy-Weinberg equilibrium?

If frequency, of ' $A$ ' allele is $0.4$ than, find out the frequency of ' $B$ ' allele and heterozygous genotype in a random mating population at equilibria

What is founder effect ?