If electrolysis of aqueous $CuSO_4$ solution is carried out using $Cu$ electrodes,the reaction taking place at the anode is:

  • A
    $H^{+} + e^{-} \rightarrow H$
  • B
    $Cu^{2+}_{(aq)} + 2e^{-} \rightarrow Cu_{(s)}$
  • C
    $S{O_{4}}^{2-}_{(aq)} - 2e^{-} \rightarrow SO_{4}$
  • D
    $Cu_{(s)} - 2e^{-} \rightarrow Cu^{2+}_{(aq)}$

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$1 \ C$ of electricity deposits:

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