If block A is moving with an acceleration of | vedclass

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Question

$2\mathrm{T}\left(\mathrm{a}_{\mathrm{A}}\right)_{\mathrm{x}}=\mathrm{T}\left(\mathrm{a}_{\mathrm{B}}\right)_{\mathrm{y}}$

$\left(a_{B}\right)_{y}=

Vedclass · Accepted Answer

$5\sqrt 5\,m/s^2$

Vedclass · Answer

$2\mathrm{T}\left(\mathrm{a}_{\mathrm{A}}\right)_{\mathrm{x}}=\mathrm{T}\left(\mathrm{a}_{\mathrm{B}}\right)_{\mathrm{y}}$

$\left(a_{B}\right)_{y}=10 \mathrm{m} / \mathrm{s}^{2}$

$a_{B}=\sqrt{5^{2}+10^{2}}=5 \sqrt{5} \mathrm{m} / \mathrm{s}^{2}$

If block $A$ is moving with an acceleration of $5\,m/s^2$, the acceleration of $B$ w.r.t. ground is

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