If the angular diameter of the Sun is about 3 | vedclass

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(C) The angular diameter $	heta$ is given as $30'$.First,convert the angular diameter from minutes to radians:$	heta = 30' = \left(\frac{30}{60}ig

Vedclass · Accepted Answer

$1.4 	imes 10^9 \, m$

Vedclass · Answer

(C) The angular diameter $	heta$ is given as $30'$.First,convert the angular diameter from minutes to radians:$	heta = 30' = \left(\frac{30}{60}ight)^\circ = 0.5^\circ$.Now,convert degrees to radians:$	heta = 0.5 	imes \frac{\pi}{180} \, 	ext{rad} = \frac{\pi}{360} \, 	ext{rad}$.The distance $r$ from the Earth is $1.5 	imes 10^{11} \, m$.The solar diameter $D$ is given by the formula $D = r 	imes 	heta$.$D = (1.5 	imes 10^{11}) 	imes \left(\frac{\pi}{360}ight)$.Using $\pi \approx 3.14159$:$D \approx 1.5 	imes 10^{11} 	imes 0.0087266 \approx 1.309 	imes 10^9 \, m$.Rounding to the nearest provided option,we get $1.4 	imes 10^9 \, m$.

Substance	Atomic Mass $(u)$	Density $(10^3\,kg\,m^{-3})$
Carbon (diamond)	$12.01$	$2.22$
Gold	$197.00$	$19.32$
Nitrogen (liquid)	$14.01$	$1.00$
Lithium	$6.94$	$0.53$
Fluorine (liquid)	$19.00$	$1.14$

If the angular diameter of the Sun is about $30'$ and its distance from the Earth is $1.5 \times 10^{11} \, m$,then the solar diameter is:

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