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(B) The letters of the word $KANPUR$ are $A, K, N, P, R, U$ (in alphabetical order).Total letters = $6$. Total permutations = $6! = 720$.Words startin

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$PRKANU$

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(B) The letters of the word $KANPUR$ are $A, K, N, P, R, U$ (in alphabetical order).Total letters = $6$. Total permutations = $6! = 720$.Words starting with:$A$: $5! = 120$$K$: $5! = 120$$N$: $5! = 120$Total so far = $120 + 120 + 120 = 360$.Words starting with $P$:$PA$: $4! = 24$$PK$: $4! = 24$$PN$: $4! = 24$Total so far = $360 + 24 + 24 + 24 = 432$.Next words starting with $PR$:$PRA$: $3! = 6$ (Total $432 + 6 = 438$)$PRK$: Remaining letters are $A, N, U$. The words are:$PRKAUN$ $(439^{th})$$PRKANU$ $(440^{th})$Thus,the $440^{th}$ word is $PRKANU$.

If all the words with or without meaning made using all the letters of the word $KANPUR$ are arranged as in a dictionary,then the word at $440^{th}$ position in this arrangement is:

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