If a spring of stiffness k is cut into two pa | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$k \propto \frac{1}{\ell}$

$\frac{ k _{ A }}{ k } =\frac{1}{ l _{ A }}$

$k _{ A } =\frac{ l _{ A }+ l _{ B }}{ l _{ A }} \cdot k$

$k _{ A }=\

Vedclass · Accepted Answer

$\frac{5}{2} k$

Vedclass · Answer

$k \propto \frac{1}{\ell}$

$\frac{ k _{ A }}{ k } =\frac{1}{ l _{ A }}$

$k _{ A } =\frac{ l _{ A }+ l _{ B }}{ l _{ A }} \cdot k$

$k _{ A }=\frac{\frac{ l _{ A }}{ l _{ B }}+1}{\frac{ l _{ A }}{ l _{ B }}} \cdot k$

$k _{ A }=\frac{\frac{2}{3}+1}{\frac{2}{3}} \cdot k$

$k _{ A }=\frac{5}{2} \cdot k$

If a spring of stiffness $k$ is cut into two parts $A$ and $B$ of length $l_{A}: l_{B}=2: 3$, then the stiffness of spring $A$ is given by

Similar Questions

What is the period of small oscillations of the block of mass $m$ if the springs are ideal and pulleys are massless ?

One-forth length of a spring of force constant $K$ is cut away. The force constant of the remaining spring will be

A particle of mass $m$ is attached to three identical springs $A, B$ and $C$ each of force constant $ k$ a shown in figure. If the particle of mass $m$ is pushed slightly against the spring $A$ and released then the time period of oscillations is

A spring executes $SHM$ with mass of $10\,kg$ attached to it. The force constant of spring is $10\,N/m$.If at any instant its velocity is $40\,cm/sec$, the displacement will be .... $m$ (where amplitude is $0.5\,m$)

In the arrangement, spring constant $k$ has value $2\,N\,m^{-1}$ , mass $M = 3\,kg$ and mass $m = 1\,kg$ . Mass $M$ is in contact with a smooth surface. The coefficient of friction between two blocks is $0.1$ . The time period of $SHM$ executed by the system is