If a spherical planet of mass M and radius R | vedclass

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(B) The moment of inertia of a solid sphere about its diameter is given by $I = \frac{2}{5} MR^{2}$.Initially,the moment of inertia is $I_{1} = \frac{

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$\frac{MR^{2}}{20}$

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(B) The moment of inertia of a solid sphere about its diameter is given by $I = \frac{2}{5} MR^{2}$.Initially,the moment of inertia is $I_{1} = \frac{2}{5} MR^{2}$.After the planet shrinks to half its size,the new radius is $R' = \frac{R}{2}$ and the new mass is $M' = \frac{M}{2}$.The new moment of inertia $I_{2}$ is calculated as:$I_{2} = \frac{2}{5} M' (R')^{2}$$I_{2} = \frac{2}{5} \left(\frac{M}{2}ight) \left(\frac{R}{2}ight)^{2}$$I_{2} = \frac{2}{5} 	imes \frac{M}{2} 	imes \frac{R^{2}}{4}$$I_{2} = \frac{2}{40} MR^{2} = \frac{MR^{2}}{20}$.

If a spherical planet of mass $M$ and radius $R$ suddenly shrinks to half its size,and its mass reduces to half,what is the new moment of inertia of the planet about its diameter?

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