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(C) To find the range $B$ of the function $f(x)$,we analyze the function in two intervals: $1$. For $-1 \leq x \leq 1$,$f(x) = 1-x$. As $x$ varies fro

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$[0,2]$

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(C) To find the range $B$ of the function $f(x)$,we analyze the function in two intervals: $1$. For $-1 \leq x \leq 1$,$f(x) = 1-x$. As $x$ varies from $-1$ to $1$,$f(x)$ varies from $1-(-1) = 2$ to $1-1 = 0$. So,the range is $[0, 2]$. $2$. For $1 Combining these,the total range of the function is $[0, 2] \cup (0, 1] = [0, 2]$. Since the function is a surjection,the codomain $B$ must be equal to the range. Therefore,$B = [0, 2]$.

If a real valued function $f:[-1,2] \rightarrow B$ defined by $f(x) = \begin{cases} 1-x, & -1 \leq x \leq 1 \\ x-1, & 1 < x \leq 2 \end{cases}$ is a surjection,then $B=$

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