If a reaction has the experimental rate expression $\text{rate} = K [A]^2[B]$,what happens to the reaction rate if the concentration of $A$ is doubled and the concentration of $B$ is halved?

  • A
    Rate becomes double
  • B
    Rate becomes eight times
  • C
    Rate becomes tripled
  • D
    No change in rate

Explore More

Similar Questions

The results given in the below table were obtained during kinetic studies of the following reaction:
$2 A + B \longrightarrow C + D$
Experiment $[A] / mol \ L^{-1}$ $[B] / mol \ L^{-1}$ Initial rate / $mol \ L^{-1} \ min^{-1}$
$I$ $0.1$ $0.1$ $6.00 \times 10^{-3}$
$II$ $0.1$ $0.2$ $2.40 \times 10^{-2}$
$III$ $0.2$ $0.1$ $1.20 \times 10^{-2}$
$IV$ $X$ $0.2$ $7.20 \times 10^{-2}$
$V$ $0.3$ $Y$ $2.88 \times 10^{-1}$

$X$ and $Y$ in the given table are respectively :

What is the order of reaction if the unit of the rate constant is $s^{-1}$?

Which of the following is an elementary reaction?

........ of a reaction cannot be determined experimentally.

For a reaction,$I^{-} + OCl^{-} \to IO^{-} + Cl^{-}$ in an aqueous medium,the rate of reaction is given by $\frac{d[IO^{-}]}{dt} = k[I^{-}][OCl^{-}]$. The overall order of reaction is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo