If a reaction has the experimental rate expression rate $= K [A]^2[B]$, if the concentration of $A$ is doubled and the concentration of $B$ is halved, the what happens to the reaction rate

If the rate of the reaction is equal to the rate constant, the order of the reaction is

For the reaction $2NO_2 + F_2 \to  2NO_2F$, following mechanism has been provided :
$N{O_2} + {F_2}\xrightarrow{{slow}}N{O_2}F + F$
$N{O_2} + {F_2}\xrightarrow{{fast}}N{O_2}F$
Thus rate expression of the above reaction can be written as

What is the molecularity of the following reaction ?

$1.$ $NH _{4} NO _{2( s )} \rightarrow N _{2( g )}+2 H _{2} O$

$2.$ $2 HI \rightarrow H _{2}+ I _{2}$

$3.$ $2 NO + O _{2} \rightarrow 2 NO _{2}$

For a reaction, $I^-+OCl^-  \to IO^-+Cl^-$ in a aqueous medium, the rate of reaction is given by $\frac{{d[{IO^ - }]}}{{dt}} = k[{I^ - }][OC{l^ - }]$ The overall order of reaction is

What is rate law ? Give a relation between rate of reaction and concentration of reactants.