If a radioactive material remains 25 % after | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The amount of radioactive material remaining is given by the formula $N = N_0 \left(\frac{1}{2}\right)^n$,where $n$ is the number of half-lives.Gi

Vedclass · Accepted Answer

$8$

Vedclass · Answer

(B) The amount of radioactive material remaining is given by the formula $N = N_0 \left(\frac{1}{2}ight)^n$,where $n$ is the number of half-lives.Given that $25 \%$ of the material remains,we have $\frac{N}{N_0} = 25 \% = \frac{25}{100} = \frac{1}{4}$.Substituting this into the formula: $\frac{1}{4} = \left(\frac{1}{2}ight)^n$.Since $\frac{1}{4} = \left(\frac{1}{2}ight)^2$,we get $n = 2$.This means $2$ half-lives have passed in $16$ days.Therefore,the duration of $1$ half-life is $T_{1/2} = \frac{16 	ext{ days}}{2} = 8 	ext{ days}$.

If a radioactive material remains $25 \%$ after $16$ days,then its half-life will be ......... days.

Similar Questions

For a radioactive element,the mean life is $\tau$. At time $t = 0$,the number of nuclei decaying per unit time is $n$. The number of nuclei that have decayed between time $0$ and $t$ is:

If $87.5 \%$ of atoms of a radioactive element decay in $6 \ days$, then the fraction of atoms of the element that decay in $8 \ days$ is

$A$ radioactive sample has ${N_0}$ active atoms at $t = 0$. If the rate of disintegration at any time is $R$ and the number of atoms is $N$,then the ratio $R/N$ varies with time as:

If ${N_0}$ is the original mass of the substance of half-life period ${T_{1/2}} = 5 \text{ years}$,then the amount of substance left after $15 \text{ years}$ is

The graph which represents the correct variation of logarithm of activity $(\log A)$ versus time $t$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module