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(C) $1$. The angular momentum of the particle about the point of projection is given by $\vec{L} = \vec{r} 	imes \vec{p}$. The torque acting on the p

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Total mechanical energy remains constant in the absence of air resistance.

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(C) $1$. The angular momentum of the particle about the point of projection is given by $\vec{L} = \vec{r} 	imes \vec{p}$. The torque acting on the particle due to gravity about the point of projection is $\vec{	au} = \vec{r} 	imes m\vec{g}$. Since $\vec{	au} 
eq 0$,the angular momentum is not constant.$2$. The linear momentum $\vec{p} = m\vec{v}$ changes because gravity exerts a constant force on the particle,causing acceleration.$3$. In the absence of air resistance,the only force acting on the particle is gravity,which is a conservative force. Therefore,the total mechanical energy of the system remains constant throughout the motion.$4$. Thus,option $C$ is the correct statement.

If a particle of mass $m$ is projected at an angle $\alpha$ with the horizontal,then :

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