Easy
If a marine fish is placed in a fresh water aquarium,will the fish be able to survive? Why or why not?
(N/A) If a marine fish is placed in a fresh water aquarium,it will not be able to survive.
Marine fishes are physiologically adapted to live in high salt concentrations (hypertonic environment).
When placed in fresh water (hypotonic environment),water enters their body cells through the process of osmosis.
Since they lack the necessary osmoregulatory mechanisms to handle such a large influx of water,their cells swell up and may burst,eventually leading to the death of the fish.
Marine fishes are physiologically adapted to live in high salt concentrations (hypertonic environment).
When placed in fresh water (hypotonic environment),water enters their body cells through the process of osmosis.
Since they lack the necessary osmoregulatory mechanisms to handle such a large influx of water,their cells swell up and may burst,eventually leading to the death of the fish.
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Similar Questions
Vasa recta refers to . . . . . . .
Which feature enables the mammalian kidney to concentrate urine in the medullary region?
Medium
View SolutionAssertion : In the descending limb of the loop of Henle,the urine is hypertonic,whereas in the ascending limb of the loop of Henle,the urine is hypotonic.
Reason : The descending limb is impermeable to sodium,while the ascending limb is impermeable to water.
Reason : The descending limb is impermeable to sodium,while the ascending limb is impermeable to water.
MediumAIIMS 2016
View Solution$A :$ In the descending limb of the loop of Henle,the urine is hypertonic,while in the ascending limb of the loop of Henle,the urine is hypotonic.
$R :$ The descending limb is impermeable to $Na^+$,while the ascending limb is impermeable to $H_2O$.
$R :$ The descending limb is impermeable to $Na^+$,while the ascending limb is impermeable to $H_2O$.
Medium
View Solution$A$: The final reabsorption of water from urine into blood occurs through the collecting duct of a mammalian nephron,resulting in the production of hyperosmotic urine.
$R$: The loop of Henle is responsible for the formation of a sodium gradient across the depth of the medullary interstitium of a mammalian kidney.
$R$: The loop of Henle is responsible for the formation of a sodium gradient across the depth of the medullary interstitium of a mammalian kidney.
Medium
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