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Question

(b) Let equation of line be $y = mx$ or $y - mx = 0$

Then applying condition for tangency,

$\left| {\frac{{ - 5 - 4m}}{{\sqrt {1 + {m^2}} }}} \r

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(b) Let equation of line be $y = mx$ or $y - mx = 0$

Then applying condition for tangency,

$\left| {\frac{{ - 5 - 4m}}{{\sqrt {1 + {m^2}} }}} \right| = 5 $

$\Rightarrow 25 + 16{m^2} + 40m = 25 + 25{m^2}$

$ \Rightarrow 9{m^2} - 40m = 0 \Rightarrow m = 0$ or $m = \frac{{40}}{9}$.

If a line passing through origin touches the circle ${(x - 4)^2} + {(y + 5)^2} = 25$, then its slope should be

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