If a function $f$ is defined by:
$\begin{cases} f(x) = x-1, & \text{when } -\infty < x < 1 \\ f(x) = 0, & \text{when } x=1 \\ f(x) = x^3-1, & \text{when } 1 < x < \infty \end{cases}$
then at $x=1$,$f$ is:

  • A
    continuous and differentiable
  • B
    continuous but not differentiable
  • C
    discontinuous and differentiable
  • D
    discontinuous and not differentiable

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Similar Questions

Let $f_1: R \rightarrow R, f_2:\left(-\frac{\pi}{2}, \frac{\pi}{2}\right) \rightarrow R, f_3:\left(-1, e^{\frac{\pi}{2}}-2\right) \rightarrow R$ and $f_4: R \rightarrow R$ be functions defined by:
$(i)$ $f_1(x)=\sin \left(\sqrt{1-e^{-x^2}}\right)$
$(ii)$ $f_2(x)=\begin{cases} \frac{|\sin x|}{\tan^{-1} x} & \text{if } x \neq 0 \\ 1 & \text{if } x=0 \end{cases}$,where the inverse trigonometric function $\tan^{-1} x$ assumes values in $\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)$.
$(iii)$ $f_3(x)=\left[\sin \left(\log_e(x+2)\right)\right]$,where,for $t \in R, [t]$ denotes the greatest integer less than or equal to $t$.
$(iv)$ $f_4(x)=\begin{cases} x^2 \sin \left(\frac{1}{x}\right) & \text{if } x \neq 0 \\ 0 & \text{if } x=0 \end{cases}$
$LIST-I$ $LIST-II$
$P$. The function $f_1$ is $1$. $NOT$ continuous at $x=0$
$Q$. The function $f_2$ is $2$. Continuous at $x=0$ and $NOT$ differentiable at $x=0$
$R$. The function $f_3$ is $3$. Differentiable at $x=0$ and its derivative is $NOT$ continuous at $x=0$
$S$. The function $f_4$ is $4$. Differentiable at $x=0$ and its derivative is continuous at $x=0$

The correct option is:

The number of real roots of the equation $e^{x-1} + \log x + x - 2 = 0$,where $x > 0$,is

Match the functions in Column $I$ with their properties in Column $II$. In the following $[x]$ denotes the greatest integer less than or equal to $x$.
Column $I$Column $II$
$A$. $x|x|$$I$. Strictly increasing and continuous in $(-1,1)$
$B$. $\sqrt{|x|}$$II$. Continuous but not differentiable in $(-1,1)$
$C$. $x+[x]$$III$. Differentiable in $(-1,1)$
$D$. $|x-1|+|x+1|+|x|$$IV$. Differentiable in $(-1,0) \cup (0,1)$
$V$. Strictly increasing and not differentiable in $(-1,1)$

The correct match is

If $y = \frac{\tan x \cos^{-1} x}{\sqrt{1-x^2}}$,then the value of $\frac{dy}{dx}$ when $x = 0$ is:

The number of points,at which the function $f(x) = \max\{6x, 2+3x^2\} + |x-1| |\cos(x^2 - 1/4)|, x \in (-\pi, \pi)$,is not differentiable,is ————

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