If a bar magnet of pole strength m and magnet | vedclass

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(C) Initial pole strength $= m$ and magnetic moment $= M = m 	imes (2l)$,where $2l$ is the length of the magnet.When a magnet is cut $n$ times parall

Vedclass · Accepted Answer

$\frac{m}{6}, \frac{M}{24}$

Vedclass · Answer

(C) Initial pole strength $= m$ and magnetic moment $= M = m 	imes (2l)$,where $2l$ is the length of the magnet.When a magnet is cut $n$ times parallel to its axis,the pole strength of each piece becomes $m' = \frac{m}{n+1}$. Here,$n=5$,so $m' = \frac{m}{5+1} = \frac{m}{6}$.When a magnet is cut $k$ times perpendicular to its axis,the length of each piece becomes $l' = \frac{l}{k+1}$. Here,$k=3$,so the new length is $2l' = \frac{2l}{3+1} = \frac{2l}{4} = \frac{l}{2}$.The pole strength remains unaffected by cuts perpendicular to the axis,so the final pole strength of each piece is $m' = \frac{m}{6}$.The new magnetic moment $M'$ is the product of the new pole strength and the new length: $M' = m' 	imes (2l') = \left(\frac{m}{6}ight) 	imes \left(\frac{2l}{4}ight) = \frac{m 	imes 2l}{24} = \frac{M}{24}$.

If a bar magnet of pole strength $m$ and magnetic moment $M$ is cut equally $5$ times parallel to its axis and again $3$ times perpendicular to its axis,then the pole strength and magnetic moment of each piece are respectively

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