If $12$ identical balls are to be placed randomly in $3$ identical boxes,then the probability that one of the boxes contains exactly $3$ balls is

  • A
    $\frac{4}{19}$
  • B
    $\frac{55}{3} \left( \frac{2}{3} \right)^{11}$
  • C
    $\frac{428 \times ^{12}C_3}{3^{11}}$
  • D
    $\frac{5}{19}$

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