If $0 < x < 1$,then $\cot ^{-1}\left( \frac{2x^2 - 1}{2x\sqrt{1 - x^2}} \right)$ is equal to
- A$2\cot ^{-1}x$
- B$\pi - 2\cos ^{-1}x$
- C$2\cos ^{-1}x$
- D$2\cos ^{-1}x - \pi$
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