If C_p and C_v denote the specific heats of n | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) According to $Mayer's$ relation,the difference between molar specific heats is given by $C_{p,m} - C_{v,m} = R$.To find the specific heat per unit

Vedclass · Accepted Answer

$C_p - C_v = \frac{R}{28}$

Vedclass · Answer

(D) According to $Mayer's$ relation,the difference between molar specific heats is given by $C_{p,m} - C_{v,m} = R$.To find the specific heat per unit mass,we divide the molar specific heats by the molar mass $M$ of the gas.For nitrogen gas $(N_2)$,the molar mass $M = 28 \ g/mol = 28 	imes 10^{-3} \ kg/mol$.Therefore,the specific heat difference is $C_p - C_v = \frac{C_{p,m}}{M} - \frac{C_{v,m}}{M} = \frac{R}{M}$.Substituting $M = 28$,we get $C_p - C_v = \frac{R}{28}$.

If $C_p$ and $C_v$ denote the specific heats of nitrogen per unit mass at constant pressure and constant volume respectively,then

Similar Questions

If a gas has $f$ degrees of freedom,what is the ratio ${C_p}/{C_v}$?

If the specific heats of a monoatomic gas and a diatomic gas are the same, which relation is valid?

For hydrogen gas $C_p - C_v = a$ and for oxygen gas $C_p - C_v = b$. The relation between $a$ and $b$ is given by:

$A$ certain amount of an ideal monatomic gas needs $20 \, J$ of heat energy to raise its temperature by $10^{\circ} C$ at constant pressure. The heat needed for the same temperature rise at constant volume will be ........ $J$.

Statement $A: C_P - C_V = R$
Statement $B: \frac{C_P}{C_V} = 1.67$

Vedclass Test Series

Exam Paper Generator

Online Exam Module