If $S_n =$$\sum\limits_{r = 0}^n {\frac{1}{{^n{C_r}}}} $ and $T_n =$$\sum\limits_{r = 0}^n {\frac{r}{{^n{C_r}}}} $ then $\frac{{{T_n}}}{{{S_n}}}$ is equal to

  • A

    $\frac{n}{2}$

  • B

    $\frac{n}{2} - 1$

  • C

    $n - 1$

  • D

    $\frac{{2n - 1}}{2}$

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