If $E$ is the electric field intensity of an electrostatic field, then the electrostatic energy density is proportional to
If $E$ is the electric field intensity of an electrostatic field, then the electrostatic energy density is proportional to
- A
$E$
- B
${E^2}$
- C
$1/{E^2}$
- D
${E^3}$
Similar Questions
Two identical capacitors, have the same capacitance $C$. One of them is charged to potential $V_1$ and the other to $V_2$. The negative ends of the capacitors are connected together. When the positive ends are also connected, the decrease in energy of the combined system is
Two identical capacitors, have the same capacitance $C$. One of them is charged to potential $V_1$ and the other to $V_2$. The negative ends of the capacitors are connected together. When the positive ends are also connected, the decrease in energy of the combined system is
$100$ capacitors each having a capacity of $10\,\mu F$ are connected in parallel and are charged by a potential difference of $100\,kV$. The energy stored in the capacitors and the cost of charging them, if electrical energy costs $108\;paise\;per\;kWh$, will be
$100$ capacitors each having a capacity of $10\,\mu F$ are connected in parallel and are charged by a potential difference of $100\,kV$. The energy stored in the capacitors and the cost of charging them, if electrical energy costs $108\;paise\;per\;kWh$, will be
Two positively charged particles $X$ and $Y$ are initially far away from each other and at rest. $X$ begins to move towards $Y$ with some initial velocity. The total momentum and energy of the system are $p$ and $E$.
Two positively charged particles $X$ and $Y$ are initially far away from each other and at rest. $X$ begins to move towards $Y$ with some initial velocity. The total momentum and energy of the system are $p$ and $E$.
A parallel plate capacitor of capacity ${C_0}$ is charged to a potential ${V_0}$
$(i)$ The energy stored in the capacitor when the battery is disconnected and the separation is doubled ${E_1}$
$(ii)$ The energy stored in the capacitor when the charging battery is kept connected and the separation between the capacitor plates is doubled is ${E_2}.$
Then ${E_1}/{E_2}$ value is
A parallel plate capacitor of capacity ${C_0}$ is charged to a potential ${V_0}$
$(i)$ The energy stored in the capacitor when the battery is disconnected and the separation is doubled ${E_1}$
$(ii)$ The energy stored in the capacitor when the charging battery is kept connected and the separation between the capacitor plates is doubled is ${E_2}.$
Then ${E_1}/{E_2}$ value is
In a uniform electric field, a cube of side $1\ cm$ is placed. The total energy stored in the cube is $8.85\mu J$ . The electric field is parallel to four of the faces of the cube. The electric flux through any one of the remaining two faces is.
In a uniform electric field, a cube of side $1\ cm$ is placed. The total energy stored in the cube is $8.85\mu J$ . The electric field is parallel to four of the faces of the cube. The electric flux through any one of the remaining two faces is.