If $y = 1 - x + \frac{x^2}{2!} - \frac{x^3}{3!} + \frac{x^4}{4!} - \dots$,then $\frac{d^2y}{dx^2} = $

  • A
    $x$
  • B
    $-x$
  • C
    $-y$
  • D
    $y$

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