If y = sqrt{sin sqrt{x}},then frac{dy}{dx} = | vedclass

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Question

(C) Given $y = \sqrt{\sin \sqrt{x}}$.Applying the chain rule,we differentiate with respect to $x$:$\frac{dy}{dx} = \frac{d}{dx}(\sqrt{\sin \sqrt{x}})$

Vedclass · Accepted Answer

$\frac{\cos \sqrt{x}}{4\sqrt{x} \sqrt{\sin \sqrt{x}}}$

Vedclass · Answer

(C) Given $y = \sqrt{\sin \sqrt{x}}$.Applying the chain rule,we differentiate with respect to $x$:$\frac{dy}{dx} = \frac{d}{dx}(\sqrt{\sin \sqrt{x}})$$= \frac{1}{2\sqrt{\sin \sqrt{x}}} 	imes \frac{d}{dx}(\sin \sqrt{x})$$= \frac{1}{2\sqrt{\sin \sqrt{x}}} 	imes \cos \sqrt{x} 	imes \frac{d}{dx}(\sqrt{x})$$= \frac{1}{2\sqrt{\sin \sqrt{x}}} 	imes \cos \sqrt{x} 	imes \frac{1}{2\sqrt{x}}$$= \frac{\cos \sqrt{x}}{4\sqrt{x} \sqrt{\sin \sqrt{x}}}$Thus,the correct option is $C$.

If $y = \sqrt{\sin \sqrt{x}}$,then $\frac{dy}{dx} = $

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