If f(x) = 3x + 10 and g(x) = x^2 - 1,then (fo | vedclass

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(A) Given $f(x) = 3x + 10$ and $g(x) = x^2 - 1$.First,find the composition $(fog)(x) = f(g(x))$.$(fog)(x) = 3(g(x)) + 10 = 3(x^2 - 1) + 10 = 3x^2 - 3

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$(\frac{x - 7}{3})^{1/2}$

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(A) Given $f(x) = 3x + 10$ and $g(x) = x^2 - 1$.First,find the composition $(fog)(x) = f(g(x))$.$(fog)(x) = 3(g(x)) + 10 = 3(x^2 - 1) + 10 = 3x^2 - 3 + 10 = 3x^2 + 7$.Let $y = (fog)(x) = 3x^2 + 7$.To find the inverse $(fog)^{-1}(x)$,we solve for $x$ in terms of $y$:$y = 3x^2 + 7$$y - 7 = 3x^2$$x^2 = \frac{y - 7}{3}$$x = (\frac{y - 7}{3})^{1/2}$.Replacing $y$ with $x$,we get the inverse function:$(fog)^{-1}(x) = (\frac{x - 7}{3})^{1/2}$.

If $f(x) = 3x + 10$ and $g(x) = x^2 - 1$,then $(fog)^{-1}$ is equal to

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