If E and F are two independent events with P( | vedclass

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(C) Given that $E$ and $F$ are independent events,we have $P(E \cap F) = P(E) \cdot P(F)$.Using the formula $P(E \cup F) = P(E) + P(F) - P(E \cap F)$,

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$\frac{1}{70}$

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(C) Given that $E$ and $F$ are independent events,we have $P(E \cap F) = P(E) \cdot P(F)$.Using the formula $P(E \cup F) = P(E) + P(F) - P(E \cap F)$,we substitute the given values:$0.5 = 0.3 + P(F) - 0.3 \cdot P(F)$$0.2 = 0.7 \cdot P(F)$$P(F) = \frac{0.2}{0.7} = \frac{2}{7}$.For independent events,$P(E|F) = P(E)$ and $P(F|E) = P(F)$.Therefore,$P(E|F) - P(F|E) = P(E) - P(F) = 0.3 - \frac{2}{7} = \frac{3}{10} - \frac{2}{7} = \frac{21 - 20}{70} = \frac{1}{70}$.

If $E$ and $F$ are two independent events with $P(E)=0.3$ and $P(E \cup F)=0.5$,then $P(E|F)-P(F|E)$ equals

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