If $f(x)=3 \sqrt[3]{x^2}-x^2$,then

  • A
    $f$ has no extrema
  • B
    $f$ is maximum at two points $x=1$ and $x=-1$
  • C
    $f$ is minimum at $x=0$
  • D
    $f$ has maximum at $x=1$ only

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