(D) Given the function $y = f(x) = \frac{ax + b}{cx - a}$.To find $x$ in terms of $y$,we perform the following steps:$y(cx - a) = ax + b$$cxy - ay = a

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(D) Given the function $y = f(x) = \frac{ax + b}{cx - a}$.To find $x$ in terms of $y$,we perform the following steps:$y(cx - a) = ax + b$$cxy - ay = ax + b$$cxy - ax = ay + b$$x(cy - a) = ay + b$$x = \frac{ay + b}{cy - a}$Since $f(x) = \frac{ax + b}{cx - a}$,replacing $x$ with $y$ gives $f(y) = \frac{ay + b}{cy - a}$.Therefore,$x = f(y)$.