If f(x) = frac{1}{{sqrt {x + 2sqrt {2x - 4} } | vedclass

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Question

(c) $f(x) = \frac{1}{{\sqrt {x + 2\sqrt {2x - 4} } }} + \frac{1}{{\sqrt {x - 2\sqrt {2x - 4} } }}$

$f(11) = \frac{1}{{\sqrt {11 + 2\sqrt {18} } }}

Vedclass · Accepted Answer

$6/7$

Vedclass · Answer

(c) $f(x) = \frac{1}{{\sqrt {x + 2\sqrt {2x - 4} } }} + \frac{1}{{\sqrt {x - 2\sqrt {2x - 4} } }}$

$f(11) = \frac{1}{{\sqrt {11 + 2\sqrt {18} } }} + \frac{1}{{\sqrt {11 - 2\sqrt {18} } }}$

$ = \frac{1}{{3 + \sqrt 2 }} + \frac{1}{{3 - \sqrt 2 }} = \frac{{3 - \sqrt 2 }}{7} + \frac{{3 + \sqrt 2 }}{7} = \frac{6}{7}$.

If $f(x) = \frac{1}{{\sqrt {x + 2\sqrt {2x - 4} } }} + \frac{1}{{\sqrt {x - 2\sqrt {2x - 4} } }}$ for $x > 2$, then $f(11) = $

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