If $(h, k)$ is the centre of the circle which passes through the origin and cuts the circles $x^2+y^2+4x+6y+12=0$ and $x^2+y^2+4x-6y+9=0$ orthogonally,then $k-2h=$

  • A
    $0$
  • B
    $1$
  • C
    -$1$
  • D
    $5$

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