If a, b, c are mutually perpendicular unit ve | vedclass

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(A) Given that $a, b, c$ are mutually perpendicular unit vectors.Therefore,$|a| = |b| = |c| = 1$ and $a \cdot b = b \cdot c = c \cdot a = 0$.We know t

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$\sqrt{3}$

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(A) Given that $a, b, c$ are mutually perpendicular unit vectors.Therefore,$|a| = |b| = |c| = 1$ and $a \cdot b = b \cdot c = c \cdot a = 0$.We know that the square of the magnitude of the sum of vectors is given by:$|a + b + c|^2 = (a + b + c) \cdot (a + b + c)$$|a + b + c|^2 = |a|^2 + |b|^2 + |c|^2 + 2(a \cdot b + b \cdot c + c \cdot a)$Substituting the known values:$|a + b + c|^2 = 1^2 + 1^2 + 1^2 + 2(0 + 0 + 0)$$|a + b + c|^2 = 1 + 1 + 1 + 0 = 3$Taking the square root on both sides:$|a + b + c| = \sqrt{3}$

If $a, b, c$ are mutually perpendicular unit vectors,then $|a + b + c| = $

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