If $\alpha$ is a root of the equation $25 \cos^2 \theta + 5 \cos \theta - 12 = 0$,for $\frac{\pi}{2} < \alpha < \pi$,then $\sin 2\alpha =$

  • A
    $\frac{-3}{5}$
  • B
    $\frac{-24}{25}$
  • C
    $\frac{-4}{25}$
  • D
    $\frac{-13}{18}$

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