If $\int \frac{x^2-1}{(x+1)^2 \sqrt{x(x^2+x+1)}} dx = A \tan^{-1}\left(\sqrt{\frac{x^2+x+1}{x}}\right) + C$,where $C$ is a constant,then $A$ equals to

  • A
    $\frac{1}{2}$
  • B
    $3$
  • C
    $2$
  • D
    $1$

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