If $\cos ^{-1}\left(\frac{x}{2}\right)+\cos ^{-1}\left(\frac{y}{3}\right)=\theta$,then $9x^2-12xy\cos \theta+4y^2=$

  • A
    $36 \sin ^2 \theta$
  • B
    $37 \sin ^2 \theta$
  • C
    $39 \sin ^2 \theta$
  • D
    $36 \cos ^2 \theta$

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