If $\theta = \tan^{-1}\left(\frac{1}{3}\right) + \tan^{-1}\left(\frac{1}{7}\right) + \tan^{-1}\left(\frac{1}{13}\right) + \tan^{-1}\left(\frac{1}{21}\right) + \tan^{-1}\left(\frac{1}{31}\right)$,then $\tan \theta =$

  • A
    $\frac{3}{5}$
  • B
    $1$
  • C
    $\frac{5}{7}$
  • D
    $\frac{7}{9}$

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