If $\left|\begin{array}{ccc}a+b+2c & a & b \\ c & 2a+b+c & b \\ c & a & a+2b+c\end{array}\right|=2$,then $a^3+b^3+c^3-3abc=$

  • A
    $2(a+b+c)^3$
  • B
    $2$
  • C
    $1$
  • D
    $0$

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