If A and B are two matrices given by A = begi | vedclass

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(B) First,calculate the determinant of matrix $A$: $|A| = 1(3 	imes 8 - 4 	imes 6) - 2(2 	imes 8 - 4 	imes 5) + 3(2 	imes 6 - 3 	imes 5) = 1(24

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$24^2$

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(B) First,calculate the determinant of matrix $A$: $|A| = 1(3 	imes 8 - 4 	imes 6) - 2(2 	imes 8 - 4 	imes 5) + 3(2 	imes 6 - 3 	imes 5) = 1(24 - 24) - 2(16 - 20) + 3(12 - 15) = 0 - 2(-4) + 3(-3) = 8 - 9 = -1$. Next,calculate the determinant of matrix $B$: $|B| = 3(3 	imes 9 - 8 	imes 2) - 2(2 	imes 9 - 8 	imes 7) + 5(2 	imes 2 - 3 	imes 7) = 3(27 - 16) - 2(18 - 56) + 5(4 - 21) = 3(11) - 2(-38) + 5(-17) = 33 + 76 - 85 = 24$. Using the property $|AB| = |A| 	imes |B|$,we get $|AB| = (-1) 	imes 24 = -24$. For a matrix $M$ of order $n 	imes n$,$|\operatorname{Adj}(M)| = |M|^{n-1}$. Here,$n = 3$,so $|\operatorname{Adj}(AB)| = |AB|^{3-1} = |AB|^2$. $|\operatorname{Adj}(AB)| = (-24)^2 = 576$. Since $576 = 24^2$,the correct option is $B$.

If $A$ and $B$ are two matrices given by $A = \begin{bmatrix} 1 & 2 & 3 \\ 2 & 3 & 4 \\ 5 & 6 & 8 \end{bmatrix}$ and $B = \begin{bmatrix} 3 & 2 & 5 \\ 2 & 3 & 8 \\ 7 & 2 & 9 \end{bmatrix}$,then the value of $|\operatorname{Adj}(AB)|$ is

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