If $(6, -k)$ and $(-3, 2)$ are conjugate points with respect to the circle $x^2 + y^2 + 6x + 4y + 12 = 0$,then $k$ equals:

  • A
    $\frac{-7}{4}$
  • B
    $\frac{7}{4}$
  • C
    $\frac{4}{7}$
  • D
    $\frac{-4}{7}$

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