If $\theta$ is in the third quadrant,then $\sqrt{4 \sin ^4 \theta+\sin ^2 2 \theta}+4 \cos ^2\left(\frac{\pi}{4}-\frac{\theta}{2}\right)=$

  • A
    $1+2 \sin \theta$
  • B
    $2$
  • C
    $1$
  • D
    $2+4 \sin \theta$

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