જો $x=\frac{2}{5}+\frac{1 \cdot 3}{2 !}\left(\frac{2}{5}\right)^2+\frac{1 \cdot 3 \cdot 5}{3 !}\left(\frac{2}{5}\right)^3+\ldots$ હોય,તો $x+\frac{1}{x}=$
- A$\frac{1+\sqrt{5}}{4}$
- B$3$
- C$\frac{5 \sqrt{5}+3}{4}$
- D$\frac{5 \sqrt{5}-3}{4}$
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