(A) We know that for any natural number $n$,the expression $x^k + y^k$ is divisible by $x+y$ if $k$ is an odd number. Since $n$ is a natural number,$2

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(A) We know that for any natural number $n$,the expression $x^k + y^k$ is divisible by $x+y$ if $k$ is an odd number. Since $n$ is a natural number,$2n-1$ is always an odd number. Therefore,$a^{2n-1} + b^{2n-1}$ is divisible by $a+b$.

Class 11 Mathematics Binomial Theorem Divisibility problems

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If $a, b$ and $n$ are natural numbers,then $a^{2n-1} + b^{2n-1}$ is divisible by

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TS EAMCET 2011 All TS EAMCET

A
$a+b$
B
$a-b$
C
$a^3+b^3$
D
$a^2+b^2$

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