If y = (cos x^{2})^{2},then frac{dy}{dx} is e | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $y = (\cos x^{2})^{2}$ Differentiating with respect to $x$ using the chain rule: $\frac{dy}{dx} = 2(\cos x^{2}) \cdot \frac{d}{dx}(\cos x^{2})$ $\

Vedclass · Accepted Answer

$-2x \sin 2x^{2}$

Vedclass · Answer

(C) $y = (\cos x^{2})^{2}$ Differentiating with respect to $x$ using the chain rule: $\frac{dy}{dx} = 2(\cos x^{2}) \cdot \frac{d}{dx}(\cos x^{2})$ $\frac{dy}{dx} = 2(\cos x^{2}) \cdot (-\sin x^{2}) \cdot \frac{d}{dx}(x^{2})$ $\frac{dy}{dx} = 2(\cos x^{2}) \cdot (-\sin x^{2}) \cdot (2x)$ $\frac{dy}{dx} = -4x \sin x^{2} \cos x^{2}$ Using the trigonometric identity $\sin 2	heta = 2 \sin 	heta \cos 	heta$,we have: $\frac{dy}{dx} = -2x(2 \sin x^{2} \cos x^{2}) = -2x \sin 2x^{2}$

If $y = (\cos x^{2})^{2}$,then $\frac{dy}{dx}$ is equal to

Similar Questions

Find the derivative of the function: $(x^{2}+1) \cos x$. (Assume that $a, b, c, d, p, q, r, s$ are fixed non-zero constants and $m, n$ are integers.)

If $y=1+x+\frac{x^2}{2!}+\frac{x^3}{3!}+\ldots$,then $\frac{dy}{dx}=$ . . . . . . .

If $f(x)$ has a derivative at $x = a,$ then $\mathop {\lim }\limits_{x \to a} \frac{xf(a) - af(x)}{x - a}$ is equal to

Find the derivative: $\frac{d}{dx} \left[ \frac{e^{ax}}{\sin(bx + c)} \right]$

Differentiate the function with respect to $x$: $\frac{\sin (a x+b)}{\cos (c x+d)}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module