If 3 tan^{-1} x + cot^{-1} x = pi,then x is e | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given the equation: $3 	an^{-1} x + \cot^{-1} x = \pi$. We know that $	an^{-1} x + \cot^{-1} x = \frac{\pi}{2}$. We can rewrite the given equati

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(B) Given the equation: $3 	an^{-1} x + \cot^{-1} x = \pi$. We know that $	an^{-1} x + \cot^{-1} x = \frac{\pi}{2}$. We can rewrite the given equation as: $2 	an^{-1} x + (	an^{-1} x + \cot^{-1} x) = \pi$. Substituting the identity $	an^{-1} x + \cot^{-1} x = \frac{\pi}{2}$ into the equation: $2 	an^{-1} x + \frac{\pi}{2} = \pi$. Subtracting $\frac{\pi}{2}$ from both sides: $2 	an^{-1} x = \frac{\pi}{2}$. Dividing by $2$: $	an^{-1} x = \frac{\pi}{4}$. Taking the tangent of both sides: $x = 	an(\frac{\pi}{4}) = 1$.

If $3 \tan^{-1} x + \cot^{-1} x = \pi$,then $x$ is equal to:

Similar Questions

If $\frac{\pi}{4} + \sum_{p=1}^{11} \tan^{-1} \left(\frac{2^{p-1}}{1+2^{2p-1}}\right) = \tan^{-1} \alpha$,then $\tan \alpha$ is equal to . . . . . . .

If $(\cos ^{-1} x)^2-(\sin ^{-1} x)^2 > 0$,then

Evaluate: $\cos ^{-1}\left(\frac{4}{5}\right)+\cos ^{-1}\left(\frac{12}{13}\right)$

If $\sin^{-1} \frac{1}{3} + \sin^{-1} \frac{2}{3} = \sin^{-1} x$,then $x$ is equal to

Find $\frac{dy}{dx}$ for $y = \cos^{-1}\left(\frac{1-x^2}{1+x^2}\right)$,where $0 < x < 1$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module