(B) The molar mass of $NaOH$ is $23 + 16 + 1 = 40 \ g \ mol^{-1}$.Number of moles of $NaOH$ = $\frac{\text{mass}}{\text{molar mass}} = \frac{5 \ g}{40

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(B) The molar mass of $NaOH$ is $23 + 16 + 1 = 40 \ g \ mol^{-1}$.Number of moles of $NaOH$ = $\frac{\text{mass}}{\text{molar mass}} = \frac{5 \ g}{40 \ g \ mol^{-1}} = 0.125 \ mol$.Volume of solution = $450 \ mL = 0.450 \ L$.Molarity $(M)$ = $\frac{\text{moles of solute}}{\text{volume of solution in } L} = \frac{0.125 \ mol}{0.450 \ L} \approx 0.278 \ M$.Therefore,the correct option is $B$.

Class 12 Chemistry Solutions Method of expressing concentration of solution

Easy

If $5 \ g$ $NaOH$ is dissolved in $450 \ mL$ of solution,the molarity of the solution is: $(Na=23, O=16, H=1 \ g \ mol^{-1})$ (in $M$)

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A
$27.8$
B
$0.278$
C
$2.78$
D
$278$

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If $5 \ g$ $NaOH$ is dissolved in $450 \ mL$ of solution,the molarity of the solution is: $(Na=23, O=16, H=1 \ g \ mol^{-1})$ (in $M$)

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The volume of a solution changes with a change in temperature. How will the molality of the solution be affected by temperature? Give a reason for your answer.

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