What is the molarity of a solution of HCl whi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given:Percentage by weight of $HCl$ = $49\%$Specific gravity of solution = $1.41 \ g/mL$Density of solution $(d)$ = $1.41 \ g/mL$Mass of $1000 \ m

Vedclass · Accepted Answer

$18.92$

Vedclass · Answer

(C) Given:Percentage by weight of $HCl$ = $49\%$Specific gravity of solution = $1.41 \ g/mL$Density of solution $(d)$ = $1.41 \ g/mL$Mass of $1000 \ mL$ of solution = $1.41 	imes 1000 = 1410 \ g$Mass of $HCl$ solute in $1000 \ mL$ solution = $49\% 	ext{ of } 1410 \ g = 0.49 	imes 1410 = 690.9 \ g$Molar mass of $HCl$ = $1 + 35.5 = 36.5 \ g/mol$Molarity $(M)$ = $\frac{	ext{Mass of solute}}{	ext{Molar mass of solute} 	imes 	ext{Volume of solution in } L}$$M = \frac{690.9}{36.5 	imes 1} = 18.929 \ M \approx 18.93 \ M$Therefore,the molarity is approximately $18.92 \ M$.

List-$I$ (Example)	List-$II$ (Type of Solution)
$A$. Humidity	$I$. Solid in solid
$B$. Alloys	$II$. Liquid in gas
$C$. Amalgams	$III$. Solid in gas
$D$. Smoke	$IV$. Liquid in solid

What is the molarity of a solution of $HCl$ which contains $49\%$ by weight of solute and whose specific gravity is $1.41$ (in $M$)?

Similar Questions

Which of the following methods of expressing concentration are unitless?

Match List-$I$ with List-$II$.

List-$I$ (Example) List-$II$ (Type of Solution)

$A$. Humidity $I$. Solid in solid

$B$. Alloys $II$. Liquid in gas

$C$. Amalgams $III$. Solid in gas

$D$. Smoke $IV$. Liquid in solid

Choose the correct answer from the options given below:

$A$ $500 \ g$ toothpaste sample has $0.2 \ g$ fluoride concentration. What is the concentration of $F^-$ in terms of $ppm$ level?

Mole fraction $(X)$ of any solution is equal to

Density of a $2.05 \ M$ solution of acetic acid in water is $1.02 \ g/mL$. The molality of the solution is ............. $mol \ kg^{-1}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module