If tan A = frac{1}{2}, then tan 3A = | vedclass

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(B) We know the formula for $	an 3A$ is $	an 3A = \frac{3	an A - 	an^3 A}{1 - 3	an^2 A}$.Given $	an A = \frac{1}{2}$.Substituting the value of $

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$\frac{11}{2}$

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(B) We know the formula for $	an 3A$ is $	an 3A = \frac{3	an A - 	an^3 A}{1 - 3	an^2 A}$.Given $	an A = \frac{1}{2}$.Substituting the value of $	an A$ in the formula:$	an 3A = \frac{3(\frac{1}{2}) - (\frac{1}{2})^3}{1 - 3(\frac{1}{2})^2}$$= \frac{\frac{3}{2} - \frac{1}{8}}{1 - 3(\frac{1}{4})}$$= \frac{\frac{12-1}{8}}{1 - \frac{3}{4}}$$= \frac{\frac{11}{8}}{\frac{1}{4}}$$= \frac{11}{8} 	imes 4 = \frac{11}{2}$.

If $\tan A = \frac{1}{2},$ then $\tan 3A = $

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