(B) Given equation: $2\cos^2 \theta - 2\sin^2 \theta = 1$Factor out $2$: $2(\cos^2 \theta - \sin^2 \theta) = 1$Using the identity $\cos 2\theta = \cos

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(B) Given equation: $2\cos^2 \theta - 2\sin^2 \theta = 1$Factor out $2$: $2(\cos^2 \theta - \sin^2 \theta) = 1$Using the identity $\cos 2\theta = \cos^2 \theta - \sin^2 \theta$,we get:$2\cos 2\theta = 1$Divide by $2$: $\cos 2\theta = \frac{1}{2}$Since $\cos 60^\circ = \frac{1}{2}$,we have:$2\theta = 60^\circ$Therefore,$\theta = 30^\circ$.